Question

9. A 90 resistor, a coil with 30 n of reactance, and a capacitor with 50 n of reactance are in series
across a 12 V ac source. The current through the resistor is *

O 9 mA
O 90 mA
O 13 mA
O 130 mA​

Answer 1

Resistance=R=90Ω

Reactance of coil=X

L

=30Ω

Reactance of capacitor=X

C

=50Ω

Impedance of circuit=X=

R

2

+(X

C

−X

L

)

2

⟹X=

90

2

+(50−30)

2

=

8100+400

Current=I=

X

E

=

8500

12

⟹I=0.13A=130mA

Answer-(D)

Answer 2

Explanation:

option d 130 mA...is correct

may it helps u ☺️