Question

9.
A
A passenger who just missed the train.
stands In the platform sadly watches
last two boggies's Of the train the
second last boggie takes time 3 sec to pass
by the passenger and the last
one takes 2 seconds to pass by?
train accelerates at constant rate How
late is passenger for the departure of the train​

Answer 1

Answer:

3.5 sec

Explanation:

Let say Velocity of Train = V  at the time of 2nd last boggie start crossing Man

Distance Covered in 3 sec

S = V3  + (1/2)a3²

S = 3V + 4.5a

Distance Covered in 2 secs

Distance Covered in 5 sec - Distance Covered in 3 sec

S = 5V + 12.5a - 3V - 4.5a  = 2V +  8a

as length of boggies are equal

3V + 4.5a = 2V +  8a

=> V = 3.5a

V = 0 + at

=> 3.5a = 0 + at

=> t = 3.5

passenger is 3.5 sec late for the departure of the train​