Question

9. (a) An object weighs 96 N when measured on the surface of the earth. What would be its weight on the surface of the moon?

Answer 1

Answer:

16 N

Explanation:

As per the provided information in the given question, we have :

• Weight of object on the Earth, Wₑ = 96 N

We've been asked to calculate the weight of the object on the surface of the moon, Wₘ.

As we know that the weight on the moon is one-sixth of the weight on the earth. Mathematically,

↠Weight on moon = ⅙ × Weight on earth

Or,

$\twoheadrightarrow \quad\underline{\boxed{\sf{W_m = \dfrac{1}{6}W_e}}}$

Substituting values in the formula,

$\\ \twoheadrightarrow\quad\sf { W_m = \dfrac{1}{6} \times 96 \; N}$

$\\ \twoheadrightarrow\quad\sf { W_m = \dfrac{1}{1} \times 16 \; N}$

$\\ \twoheadrightarrow\quad\underline{\boxed{\textbf{\textsf{W}}_{\textbf{\textsf{m}}} = \textbf{\textsf{16 \; N}} }}$

∴ Weight of the object on the moon is 16 N.

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More Information :

• Weight is nothing but the force with which the bodh is attracted towards the centre of the earth.

• It is a vector quantity.

• Its SI unit is Newton.

• Weight = Mass × Acceleration due to gravity ; W = mg

• Weight of the body changes with the change in acceleration due to gravity.

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Answer 2

Answer:

Question :-

• An object weighs 96 N when measured on the surface of the earth. What would be its weight on the surface of the moon.

Given :-

• An object weighs 96 N when measured on the surface of the earth.

To Find :-

• What is the weight on the surface of the moon.

Formula Used :-

$\clubsuit$ Weight of Moon Formula :

$\small \bigstar \: \: \sf\boxed{\bold{\pink{Weight_{(Moon)} =\: \dfrac{1}{6} \times Weight_{(Earth)}}}}\: \: \: \bigstar$

Solution :-

Given :

$\mapsto \bf Weight_{(Earth)} =\: 96\: N$

According to the question by using the formula we get,

$\small \implies \bf Weight_{(Moon)} =\: \dfrac{1}{6} \times Weight_{(Earth)}$

$\implies \sf Weight_{(Moon)} =\: \dfrac{1}{6} \times 96$

$\implies \sf Weight_{(Moon)} =\: \dfrac{1 \times 96}{6}$

$\implies \sf Weight_{(Moon)} =\: \dfrac{\cancel{96}}{\cancel{6}}$

$\implies \sf Weight_{(Moon)} =\: \dfrac{16}{1}$

$\implies \sf Weight_{(Moon)} =\: 16$

$\implies \sf\bold{\red{Weight_{(Moon)} =\: 16\: N}}$

$\small \sf\bold{\purple{\underline{\therefore\: The\: weight\: on\: the\: surface\: of\: the\: moon\: is\: 16\: N\: .}}}$

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