Question

9. A and B can do a piece of work in 18 days; B and C in 24 days; C and A in 36 days. How long will
it take them to do the work together?
In what time can each finish it, working alone?​

Answer 1

Answer:

A+B=18 days

B+C=24 days

C+A=36 days

to make it simpler lets find the LCM

=504 units(and i mean by units-the amount of work completed)

Now lets find in one day how much units they solve

A+B=$\frac{504}{18}$=28 units

B+C= $\frac{504}{24}$=21 units

C+A=$\frac{504}{36}$=14 UNITS

so if we wanna add all

=2A+2B+2C=(28+21+14)

   OR

2(A+B+C)=63

A+B+C=63/2

A+B+C=31.5 UNITS=1 DAY

B+C=31.5/2=15.75UNITS

C=504/15.75=32 DAYS

Likewise u can do the rest

I dont wanna give the full answer or else u wont learn anything frm it

TY

MARK ME AS THE BRAINLIEST

HAPPY TO HELP :)

Step-by-step explanation: