9. 'A' and 'B' can do a piece of work in 45 days and 40 day's respec-
tively. They began to do the work together, but 'A' leaves after some
days and then 'B' completed the remaining part of the work in 23
days. The number of days, after which 'A' left the work was
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Solution:
(A+B)'s 1 day's work = 145+140=17360145+140=17360
Work done by B in 23 days = 1×2340=23401×2340=2340
Remaining work = 1−2340=17401−2340=1740
Now, 1736017360 work was done by (A+B) in 1 day.
17401740 work was done by (A+B) in 1×36017×1740=9 days1×36017×1740=9 days
Therefore, A left after 9 days.
(A+B)'s 1 day's work = 145+140=17360145+140=17360
Work done by B in 23 days = 1×2340=23401×2340=2340
Remaining work = 1−2340=17401−2340=1740
Now, 1736017360 work was done by (A+B) in 1 day.
17401740 work was done by (A+B) in 1×36017×1740=9 days1×36017×1740=9 days
Therefore, A left after 9 days.
Answered by
1
9 days . hope this answer helped u
janu8599:
thanx
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