9.A and B together can do a piece of work in 15 days, while B alone can
finish it 20 days. In how many days can A alone finish the work?
Answers
Answered by
1
60 days
step by step
(A + B)’s 1 day’s work = 1/15
B’s 1 day’s work = 1/20
∴ A’s 1 day’s work = 1/15 - 1/20
(take LCM of 15 and 20)
then we will get 60. Multiply both the numbers so that the denominator comes 60.
therefore,
4-3/60 = 1/60
∴ A alone will do the work in 60 days.
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Answered by
1
Answer:
60 days
step by step
(A + B)’s 1 day’s work = 1/15
B’s 1 day’s work = 1/20
∴ A’s 1 day’s work = 1/15 - 1/20
(take LCM of 15 and 20)
then we will get 60. Multiply both the numbers so that the denominator comes 60.
therefore,
4-3/60 = 1/60
∴ A alone will do the work in 60 days.
Step-by-step explanation:
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