9(a+b)3 -25(a+b) solve
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Answered by
78
9(a + b)^3 - 25(a + b)
Let (a + b) = w
9w^3 - 25w
w(9w^2 - 25)
w[(3w)^2 - 5^2]
Use formula a^2 - b^2 = (a+b)(a-b)
w [(3w + 5)(3w - 5)]
As w = a + b
(a + b) [(3(a + b) + 5)(3(a + b) - 5)]
(a + b) [(3a + 3b + 5)(3a + 3b - 5)]
(a + b)(3a + 3b + 5)(3a + 3b - 5)
Let (a + b) = w
9w^3 - 25w
w(9w^2 - 25)
w[(3w)^2 - 5^2]
Use formula a^2 - b^2 = (a+b)(a-b)
w [(3w + 5)(3w - 5)]
As w = a + b
(a + b) [(3(a + b) + 5)(3(a + b) - 5)]
(a + b) [(3a + 3b + 5)(3a + 3b - 5)]
(a + b)(3a + 3b + 5)(3a + 3b - 5)
wizardaditya:
wrong answer
write correct answrr
Maybe the way you wrote the expression in question is incorrect.
ya
wrong answer
Answer edited.
write answer
Mark it as brainliest.
Answered by
10
here g(a+b)^3 - 25 (a+b)
9[a^3 + b^3 + 3a^2b + 3ab^2] - 25(a+b)
9a^3 + 9b^3 + 27a^2b + 27ab^2 - 25(a+b)
9a^3 + 9b^3 + 27a^2b +27ab^2 -25a -25b
here last answer you can common any number
9[a^3 + b^3 + 3a^2b + 3ab^2] - 25(a+b)
9a^3 + 9b^3 + 27a^2b + 27ab^2 - 25(a+b)
9a^3 + 9b^3 + 27a^2b +27ab^2 -25a -25b
here last answer you can common any number
No. We can’t take until it is said.
ok i edit
yes
3 is the power
oo but you have to write as ^3
sorry
its ok no problem
cheris please solve
ok i see
this is the factorise
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