Question

9. A, B and C forms an isosceles triangle which
of these are not coordinate of C:.
(a) (4, 4)
(b) (8,0)
(c) (6, 2)
(d) (2,6).​

Answer 1

Option c 6 2 is the answer

Answer 2

Option C is correct answer.

Step-by-step explanation:

Given coordinate are (4,4), (8,0), (6,2) and, (2,6).

Let that coordinate A (4,4), B(8,0), C(6,2) and, D(2,6).

Lets find the distance between them, those are real coordinate of the isosceles triangle.

Now,

AB

$=\sqrt{(8-4)^{2}+(0-4)^{2}}$

$=\sqrt{16+16} \\=\sqrt{32}$

BC

$= \sqrt{(6-8)^{2}+(2-0)^{2}}$

$=\sqrt{4+4} \\=\sqrt{8}$

AC

$=\sqrt{(6-4)^{2}+(2-4)^{2}}\\=\sqrt{4+4} \\=\sqrt{8}$

AD

$=\sqrt{(2-4)^{2}+(6-4)^{2}}\\=\sqrt{4+4} \\=\sqrt{8}$

Therefore, option C (6,2) is not the coordinate of triangle ABC.