Question

9. A bag contains ten red balls and six blue balls. What are the probabilities of randomly
drawing (1) a red ball and (ii) a blue ball from the bag?
10. A ​

Answer 1

Answer:

Step-by-step explanation:

Assuming every single ball has an equal chance of being drawn, then if B is the probability of drawing a blue ball and R is the probability of drawing a red ball:

B + R = 1,

since either a red or blue ball will be drawn. Since each ball has an equal chance of being drawn:

16 p = 1, or

p = 1/16

where p is the chance to draw a single ball. Since there are 10 red balls, there are ten independent and different ways to draw a red ball, which means that

R = 10 p = 10/16 = 5/8.

You can either apply the first equation to find that

B = 1 - R = 3/8

or state directly that

B = 6 p = 6/16 = 3/8

since there are six independent and different ways to draw a blue ball from the bag.

Hope it helped you...........