Question

9.
A ball of mass 2 kg is thrown with velocity
10 m/s, at an angle 30° to the horizontal and
another ball of same mass is thrown at an angle of -
60° to the horizontal, with same speed. The ratio of
their range will be
​

Answer 1

Explanation:

range of a projectile=u^2sin2teta/g

when u apply this u will get an answer.

r1=u1^2sin2teta/g

r1=10^2sin2(30°)/10

r1=100×sin60°/10

r1=100×√3/2/10

when u solve this u will get,

r1=5√3

like that when u solve r2 ,

r2=100×sin2(60°)/10

r2=100×sin120°/10

r2=100×√3/2/10

r2=5√3

so,

r1/r2=5√3/5√3

r1/r2=1/1

Answer 2

Answer:

see the attachment

hope it helps you

follow me ✔✔