Question

9.
A body of mass 1 kg is placed at a distance of 2 m from another body of mass 10 kg.
At what distance from the body of 1 kg, another body of mass 5 kg be placed so that
the net force of gravitation acting on the body of mass 1 kg is zero?​

Answer 1

Answer:

4.5m

Explanation:

Answer 2

Explanation:

$f = g \times \frac{m \times n}{ {r}^{2} }$

$0 = g( \frac{10}{4} + \frac{5}{x2 } )$

Solving

X=4.5 m in opposite side