9. A body starts from rest and moves with a uniform acceleration of 4m/s2 until it travels a distance of 800m, find the find velocity?
Answers
Answered by
197
a=4 m/s2
s=800m
u=0 m/s
s=ut+ 1/2 at2
800=0+1/2*4*t2
800=2t2
400=t2
t=20 s
a=(v-u)/t
4=v-0/20
80=v
v=80 m/s
s=800m
u=0 m/s
s=ut+ 1/2 at2
800=0+1/2*4*t2
800=2t2
400=t2
t=20 s
a=(v-u)/t
4=v-0/20
80=v
v=80 m/s
Answered by
111
Given :
Uniform acceleration =a=4m/s2
Time=t=?
Initial speed =u=0m/s
Distance =800m
Final velocity =v=?
From Second equation of motion:
S=ut + 1/2at^2
800=0*t +1/2 4*t^2
t^2=400
t=20sec
V=u+at
=0+4×20
=80m/s
Therefore final velocity =80m/s
Uniform acceleration =a=4m/s2
Time=t=?
Initial speed =u=0m/s
Distance =800m
Final velocity =v=?
From Second equation of motion:
S=ut + 1/2at^2
800=0*t +1/2 4*t^2
t^2=400
t=20sec
V=u+at
=0+4×20
=80m/s
Therefore final velocity =80m/s
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