Question

9. A body starts from rest and moves with an uniform acceleration. The ratio of distance covered in the nth second to the distance covered in 'n seconds is​

Answer 1

Answer:

The distance covered in (2n-1):n^2.

Explanation:

Distance covered in nth sec is given by : u+ \frac{a}{2} (2n-1)

Distance covered in n sec : un+ \frac{a}{2} (n)^{2}

Since both starting from rest. u=0

Ratio= (a)(2n-1)/2: an²/2

= (2n-1):n²

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Answer 2

Answer:

Explanation:

For nth second,

x = u + 0.5a(2n – 1)

at rest u = 0

thus

x = 0.5a(2n-1)...................(1)

For n second,

y = 0 + 0.5an^2....................(2)

dividde the eqns,

x/y = (2n-1)/n^2