Question

9. A book of mass 0.5 kg has its length 75 cm and breadth 25 cm. Then the moment of inertia about an axis perpendicular to the book and passing through the centre of gravity of the book is
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Answer 1

Explanation:

Ma sq./12+Mb sq./12=

10/384kg-m sq.

Answer 2

The moment of inertia is 0.02604 kg-m²

Explanation:

Given that,

Mass of book = 0.5 kg

Length = 75 cm

Breath = 25 cm

We need to calculate the moment of inertia about an axis

Using formula of moment of inertia

$I=\dfrac{Ma^2}{12}+\dfrac{Mb^2}{12}$

Put the value into the formula

$I=\dfrac{1}{2\times12}((\dfrac{3}{4})^2+(\dfrac{1}{4})^2)$

$I=0.02604\ kg-m^2$

Hence, The moment of inertia is 0.02604 kg-m²

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Topic : moment of inertia

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