Question

9. A boulder of mass 10 kg rolls over a cliff and reaches the beach below with a velocity of 15 m/s. Find:
a. the kinetic energy of the boulder as it lands;
b. the potential energy of the boulder when it was at the top of the cliff
c. the height of the cliff.

Answer 1

Answer:

1125j

Explanation:

➡Kinetic energy = ½×mv²

➡Kinetic energy = ½×10×15²

➡Kinetic energy= 5 × 225 = 1125 Joule (J)

\small \fbox {The kinetic energy = 1125 J}

The kinetic energy = 1125 J

Answer 2

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1125j

➡Kinetic energy = ½×mv²

➡Kinetic energy = ½×10×15²

➡Kinetic energy= 5 × 225

= 1125 Joule (J)

The kinetic energy = 1125 J

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