Question

9. A box is initially at rest on a horizontal,frictionless table. If a force of 10 Newtonsacts on the box for 3 seconds, what is themomentum of the box at the end of 3second interval ?

Answer 1

Answer:

• The momentum (P) after the 3 second will be 30 N-m.

Given:

1. Applied Force (F) = 10 N.
2. Time period (t) = 3 seconds

Explanation:

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Newton's Second Law:

It states that the Rate of change of momentum is directly proportional to the Applied External force on the body.

Expression:

• F = P / t

Dimensional formula:

• M L T⁻²

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$\rule{300}{1.5}$

From the formula we know,

⇒ F = P / t

Where,

• F Denotes Force.
• P Denotes Momentum.
• t Denotes Time period.

Now,

⇒ F = P / t

Substituting the values,

⇒ 10 N = P / 3 sec

⇒ 10 = P / 3

⇒ P = 10 × 3

⇒ P = 30

⇒ P = 30 N-m

∴ The momentum (P) after the 3 second will be 30 N-m.

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Answer 2

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