Math, asked by anandguptar178, 9 months ago

9. A can do a piece of work in 12 days and B can do it in 15 days. A starts the work and
does it for 3 days, 'Ihe remaining work is done by B alone. In what lime did B finish
the remaining work?

Answers

Answered by lsrini
2

Answer:

Step-by-step explanation:

A = 12 days

A's 1 day work = 1/12

B = 15 days

B's 1 day work = 1/15

Together work = A + B = 1/12 + 1/15

                          = 5/60 + 4/60

                          = 9/60

But ,

       A starts the work and  does it for 3 days = 3 * 9/60

                                                                             =  9/20

Remaining work = 1 - 9/20

                              = 11/20

There Fore ,

                     B will complete the work in  11/20 *20

                                                                 = 11 Days

Hope this helps you

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