Question

9. A car starting from rest at a constant acceleration covers a distance ’s’ in time interval ’t’. It covers a distance s2 in the next time interval at the same acceleration. The statement which is true is
a. S2 = S1 b. S2 = 2 S1 c. S2 = 3 S1 d. S2 = 4 S1 ​

Answer 1

Answer:

The relation between S2 and S1 is S2 = 3S1

Explanation:

Initial velocity u = 0 m/s

The distance travelled in the first time interval ,S1

S1 = ut + $\frac{1}{2} \times a\times t^{2}$

S1 = $\frac{1}{2} \times a\times t^{2}$ (since u=0)

Velocity after first time interval,

     v = u + at

     $v=0+at=at$

It covers a distance s2 in the next time interval at the same acceleration.

$S2=ut+\frac{1}{2}at^2$

here u = at

$\begin{aligned}S2=(at\times t)+\frac{1}{2}at^2\\=\frac{3}{2}at^2\end{aligned}$$= 3S1$

S2 = 3S1