9.
A cubical vessel of height 1 m is full of water. The minimum work done in taking water-out from vessel will be
(1) 5000 j
(2) 10000 J
(3) 5 J
(4) 10j
Answers
Answered by
38
Answer:
Explanation:
Work = Change in Potential energy
= Final Potential energy - Initial Potential energy
= mgL - mgL/2
= mgL/2
= (ALd gL)/2
= (1^2 * 1 * 10^3 * 10 * 1)/2
= 5 kJ
Answered by
2
Answer:
Work = Change in Potential energy
= Final Potential energy - Initial Potential energy
= mgL - mgL/2
= mgL/2
= (ALd gL)/2
= (1^2 * 1 * 10^3 * 10 * 1)/2
= 5 kJ
Explanation:
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