Question

9 A force of
of 200 is applied to a cylinder of
ci reculare radius 2m. Find
the normal stress
/​

Answer 1

Answer:

Normal stress = Force / Area of cross section.

Area of the circular part of the cylinder ,= 22/7 x 2 x 2 = 88/7 m^2.

Normal stress = 200/88/7 = 200 x 7/88 = 15.9 Pa or 16 Pa.

Answer = 16 Pa.