Math, asked by devojusrinu00713, 6 months ago

9
A man buys 100 pomegranates at 50 Paise
each and 50 Kiwi fruits at 60 Paise each.
10% of the pomegranates and Kiwi fruits
are spoilt. The man sells the remaining
pomegranates at 70 Paise each and kiwi
fruits at Rs.1 each. The profit made, as
percentage of the cost is​

Answers

Answered by Anonymous
3

Answer:

No. of pomegranates he buys = 100

Cost Price of each pomegranate = 50 paise

Total cost price of pomegranates = 100 x 50 = 5000 paise = 50 rupees

No. of kiwis he buys = 50

Cost Price of each kiwi = 60 paise

Total cost price of kiwis = 50 x 60 = 3000 paise = 30 rupees

Percentage of pomegranates spoilt = 10% of 100 = 10/100 x 100 = 10 fruits

Percentage of kiwis spoilt = 10% of 50 = 10/100 x 50 = 5 fruits

Total cost price of pomegranates excluding spoilt fruits' price =

5000 - 10 x 50 = 5000 -500 = 4500 paise = 45 rupees

Total cost price of kiwis excluding spoilt fruits' prices =

3000 - 5 x 60 = 3000 - 300 = 2700 paise = 27 rupees

Total cost price of both fruits excluding spoilt fruits' prices = 45 + 27 = 72

No. of pomegranates he sells = 90 fruits ( because 10 are spoilt )

Selling price per pomegranate = 70 paise

Total money earned from pomegranate = 90 x 70 = 4900 paise = 49 rupees

No. of kiwis he sells = 45 fruits ( because 5 are spoilt )

Selling price per kiwi = 100 paise

Total money earned from kiwis = 45 x 100 = 4500 paise = 45 rupees

Total money earned from both fruits = 49 + 45 = 94 rupees

Profit = Selling price - Cost price = 94 - 72 = 22 rupees

Profit in percentage = profit/ cost price x 100 = 22/72 x 100 = 30.5 %

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