Question

9. A man divided 62500 among his four sons such that
four times the share of his first son, three times the
share of his second son, two times the share of his
third son and the share of his fourth son are all equal.
Find the share of each of his sons.​

Answer 1

Answer: (Not sure)

And first son= 25000

Second son= 18750

Third son= 12500

Fourth son = 6250

Step-by-step explanation:

Assume, shares as 4x, 3x, 2x, x respectively for 1st, 2nd , 3rd and 4th son.

4x+3x+2x+x = 62500

x= 6250

1st son= 4x = 25000

2nd son= 3x = 18750

3rd son= 2x = 12500

4th son= x= 6250

Answer 2

Answer:

1st son 7500, 2nd son=10,000, 3rd son=15,000 4th son=30,000

Step-by-step explanation:

total amount given is 62500

let the 1 son be A, 2nd son be B, 3rd son be C, 4th son be D

4(A)=3(B)= 2(C)= 1(D)

so the ratio of A:B:C:D= 3:4:6:12

Therefore, 62500/25= 2500

A=3×2500= 7500

B= 4×2500=10,000

C= 6×2500=15,000

D= 12×2500=30,000