Question

9. A man goes 30 km due north and then 40 km due east. How far away is he from his initial position ?
​

Answer 1

Answer:

30 km upward then 40 km right. This forming a right triangle. Hupotenuse or distance=

H^2= B^2+P^2

H^2= 30^2+40^2

H^2= 900km^2+1600km^2

H^2= 2500km^2

h = \sqrt{2500 {km}^{2} }h=2500km2

Hypotenuse= 50km

Hope it helps☺

Answer 2

Answer:

50 km

Step-by-step explanation:

30^2+40^2=Distance from his initial position^2

=root (900+1600)

=root 2500

=50 km

Mark me as Brainliest