9. A man saves 3,000 every year and
invests it at the end of the year at 10%
compound interest. Calculate the total
amount of his savings at the end of the third
year.
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Answer:
3000x110/100 = 3300 .2ndyr
6300x110/100 = 69 30. 3rdyr
9300 at the end of 3rd year
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