Question

9. A marvel lying at rest is struck by another marble of same type at a speed of 5m/s.
After collision if first marble comes to rest, calculate the speed of second marble.
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Answer 1

Explanation:

m(12)+m(0)=mv

1

+mv

2

=0⇒v

1

+v

2

=12

−

12−(0)

v

1

−v

2

=1⇒v

1

−v

2

=−12

thus,v

1

=0

v

2

=12,sovelocityoffirstaftercollisionis0.

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