9. A motor cycle of mass 480 kg changes its speed from 3 m/s to 8 m/s. The change in KE
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Answer:
kE in first case=
1/2. mv²= 1/2×480×3²=2160J
KE in second case=
1/2.mv²=1/2×480×8²=15360J
so change will be 15360-2160=13200J
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