Question

9. A multistoreyed building has 25 floors above ground level each of height 5m. It has also three
floors in the basement each of height 5m. A lift in building moves at a rate of 1m/s. If a man
starts from the 50m above the ground, how long will it take to him to reach the 2nd floor of the
basement?

Answer 1

Answer:

20 minutes

Step-by-step explanation:

☆ Total distance from 3rd floor basement to 25th floor

=140 metres

starting point: 50 metres above ground (+50) = 10th floor

ending point: second floor of basement (-2)

Distance between starting point and ending point= 50 metres(above ground) + 10 metres(below ground basement)

= 60 metres

speed of elevator = 1 metre per second

• 60 metres in floors= 60* 5 = 300 metres

Time taken to reach 5 metres or one floor

= 5 seconds

to reach 300 metres

= 300 seconds or 5 minutes

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Answer 2

$\red{\underline{\underline{Answer:}}}$

$\sf{The \ lift \ will \ take \ 1 \ minute \ to}$

$\sf{reach \ 2^{nd} \ floor \ in \ the \ basement.}$

$\sf\orange{Given:}$

$\sf{\implies{A \ multistorey \ building \ has \ 25 \ floors}}$

$\sf{above \ the \ ground \ level \ and \ and \ three}$

$\sf{floors \ in \ the \ basement.}$

$\sf{\implies{Height \ of \ each \ floor=5 \ m}}$

$\sf{\implies{Speed \ of \ lift=1 \ m \ s^{-1}}}$

$\sf\pink{To \ find:}$

$\sf{The \ time \ taken \ by \ lift \ to \ reach}$

$\sf{2^{nd} \ floor \ in \ basement \ from \ 50 \ m}$

$\sf{above \ ground \ level.}$

$\sf\green{\underline{\underline{Solution:}}}$

$\sf{Each \ floor \ of \ basement=5 \ m}$

$\sf{\therefore{Distance \ till \ 2^{nd} \ floor=10 \ m}}$

$\sf{Total \ distance=50+10}$

$\sf{\therefore{Total \ Distance=60 \ m}}$

$\sf{Speed \ of \ lift=1 \ m \ s^{-1}}$

$\boxed{\sf{Time=\frac{Distance}{Speed}}}$

$\sf{\therefore{Time \ taken \ by \ lift \ to \ reach}}$

$\sf{2^{nd} \ floor \ in \ basement=\frac{60}{1}}$

$\sf{=60 \ seconds}$

$\sf{=1 \ minute}$

$\sf\purple{\tt{\therefore{The \ lift \ will \ take \ 1 \ minute \ to}}}$

$\sf\purple{\tt{reach \ 2^{nd} \ floor \ in \ the \ basement.}}$