Question

9. A number is divided into two parts such that one part is 33 more than the other. Find the numbers,if the ratio between them is 3:4.
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Answer 1

Answer:

Since the two parts are in the ratio 5:3, then let the first number be 5x and second number be 3x. As second number is 10 more than the other, so it will be 3x+10.

5x=3x+10

2x=10

x=5

The first number becomes 5(5)=25 and second number becomes 3(5)=15.

The new number will be 25+15=40

Answer 2

Answer:-

$\sf{The \ numbers \ are \ 99 \ and \ 132 \ respectively. }$

Given:

• A number is divided into two parts such that one part is 33 more than the other number.

• Ratio of the numbers is 3:4.

To find:

The numbers.

Solution:-

$\sf{Let \ the \ constant \ be \ n.}$

$\sf{\therefore{Numbers \ are \ 3n \ and \ 4n}}$

$\sf{According \ to \ the \ given \ condition. }$

$\sf{4n-3n=33}$

$\boxed{\sf{\therefore{n=33}}}$

$\sf{The \ numbers \ are}$

$\sf{\implies{3n=3(33)=99}}$

$\sf{\implies{4n=4(33)=132}}$

$\sf\purple{\tt{\therefore{The \ numbers \ are \ 99 \ and \ 132 \ respectively. }}}$