Question

9. A pair of die is thrown. Find the probability of getting a sum of 10 or more, if 5 appears an the first die.
(Hint: Favourable cases are (5.5) and (5.6)]​

Answer 1

Answer:

First,

Total outcomes=6 &6=12

probability of getting a number more than 10=12-10=2

probability= 2

favourable cases of 5= 1

becomes total 5 in a dice is1

favourable cases of six =1 because the six in a dice is only one

So, the probability of getting 5,5&6,6 is 1

at first they have said that there are two dices

So, each dice have6&6 total outcomes which makes it 12