Question

9. A pair of die is thrown. Find the probability of getting a sum of 10 or more, if 5 appears an the first die?
(Hint: Favourable cases are (5, 5) and (5, 6)].
please give me answer ​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

$answer$

In throwing a dice, total possible outcomes

= 1, 2, 3 , 4, 5, 6,

so, n(S) = 6

For two dice, n(S) = 6 ×6 = 36

Favorable cases where the sum is 10 or more with 5 on first die = n(E) = 2

Hence, the probability of getting a sum of 10 or more with 5 on 1st die = n(E) \ n(S)

= 2/36 = 1\18

hope it helps u

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