Question

9. A parallel plate air capacitor of value C0 is charged to a potential V0, between
the plates and +q0, is charge on one plate. Separation between plates is d. A
dielectric of dielectric constant K = 3 fills the space between the plates. Which
of these quantities will change and why. (i) capacitance (ii) charge (iii) po-
tential difference and (iv) field density?​

Answer 1

Answer:

(i) C=3Co

(ii) V=Vo/3

(iii) Decrease

Explanation:

(i) capacitance increase K times.

(ii) As charge remain constant so by using Q=CV

you will get potential decrease by K time.

(iii) Decrease due to induced electric field inside

dielectric material..

E=Eo-Eind