Question

9. A particle starts moving from the position of rest under a constant acceleration. It travels a distance x in the first 10 sec and distance y in the next 10 sec, then
a) 33.3 km/hr b) 2013 km/h c) 25/2 km/hr d) 35 km/hr​

Answer 1

Answer:

initially velocity is zero, and acceleration is a, so distance covered in 10 sec is x=21a102=50a 

now distance covered in total 30 sec is x+y=21a302=450a

so y=400a,x=50a

so y=8x

Answer 2

Answer:

hlo dear u can relate this answer and solve ur question

Explanation:

initially velocity is zero, and acceleration is a, so distance covered in 10 sec is x=21a102=50a 

now distance covered in total 30 sec is x+y=21a302=450a

so y=400a,x=50a

so y=8x

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