Question

9.A person sitting on the top of a tall building is dropping balls at regular intervals of one second. When the 6th ball is being dropped, the positions of the 3rd, 4th, 5th balls from the top of the building are respectively

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Answer 1

Answer:

4.9m

Step-by-step explanation:

When the 6th ball is being dropped, the time passed since the balls have been dropped are-

3rd ball: 3 seconds

4th ball: 2 seconds

5th ball: 1 second

Hence the distance through which the balls fell in the time is:

3rd ball:

2

1

gt

2

=

2

1

×9.8×3

2

=44.1m

4th ball:

2

1

gt

2

=

2

1

×9.8×2

2

=19.6m

5th ball:

2

1

gt

2

=

2

1

×9.8×1

2

=4.9m

hope it helps you.....have a good day