9. A photograph of a bacteria enlarged 40,000 times attains a length of 6 cm as shown in the
diagram. What is the actual length of the bacteria? If the photograph is enlarged 10,000
times only, what would be its enlarged length?
خاک
Answers
If two quantities increase or decrease together in such a
manner that the ratio of their corresponding values remain constant, we say that the two quantities vary directly.
In other words x and y are said to vary directly if X/y = k
, where k is a positive constant.
In direct Proportion
x/y= k
x=ky
So we can find value of k from known values, and then use the
formula to calculate the unknown values.
When two quantities x and y are in direct proportion (or vary directly) they are
also written as x∝y.
=========================================================
Solution:
[Table is in the attachment]
Let the actual length of bacteria be ‘x’
& enlarged length be y cm.
Here the number of times the photograph of bacteria was enlarged & the length of the bacteria are in direct
proportion.
5/50000=x /1
X= 1/10000
x=0.0001cm
x=10^-4
Hence, the actual length of bacteria is
10^-4
Let the length of the bacteria when the
photograph of bacteria was enlarged 20000 times be y
5/50000 = y/20000
y × 50000 = 5× 20000
y= 5× 20000/50000
y= 2cm.
Hence, the enlarged length of the bacteria
is 2cm.
==========================================================
Hope this will help you....
Answer:
If two quantities increase or decrease together in such a
manner that the ratio of their corresponding values remain constant, we say that the two quantities vary directly.
In other words x and y are said to vary directly if X/y = k
, where k is a positive constant.
In direct Proportion
x/y= k
x=ky
So we can find value of k from known values, and then use the
formula to calculate the unknown values.
When two quantities x and y are in direct proportion (or vary directly) they are
also written as x∝y.
=========================================================
Solution:
[Table is in the attachment]
Let the actual length of bacteria be ‘x’
& enlarged length be y cm.
Here the number of times the photograph of bacteria was enlarged & the length of the bacteria are in direct
proportion.
5/50000=x /1
X= 1/10000
x=0.0001cm
x=10^-4
Hence, the actual length of bacteria is
10^-4
Let the length of the bacteria when the
photograph of bacteria was enlarged 20000 times be y
5/50000 = y/20000
y × 50000 = 5× 20000
y= 5× 20000/50000
y= 2cm.
Hence, the enlarged length of the bacteria
is 2cm.