Question

9. A race track is in the form of a ring whose inner circumference is 528 m and the outer
circumference is 616 m. Find the width of the track.
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Answer 1

Answer:

14 meter will be width of the track

Answer 2

$\bigstar \underline{\underline{\sf Given:-}}$

• Inner circumference =528m.
• Outer circumference =616m.

$\bigstar \underline{\underline{\sf To\ find:-}}$

• Width of the track.

$\bigstar \underline{\underline{\sf Solution:-}}$

We know:

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❥Circumference of circle=2πr

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Now,

Let 'r' be inner radius & 'R' be outer radius.

➲Outer Circumference  =616m

=> 2πr = 616  

=> πr = 308

=> r = 308 × 7/22

=> 14 × 7 = 98

=> r=98m

➲ Inner Circumference = 528m.

=> 2πR = 528

=> πR = 264

=> R = 264 × 7/22

=> 12 × 7 = 84

=> R=84m.

Width of track:-

➲The width = Outer radius - inner radius

=> (R – r) = (98 – 84) = 14m

Therefore,the width of track is 14m.

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HOPE IT HELPS!