9. A road roller takes 750 complete revolutions to move
once over to level a road. Find the area of the road if the
diameter of a road roller is 84 cm and length is 1 m.
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Answer:
continuing from above
h = 1 m
r = 42/100 m
curved surface area of roller = 2πrh
= 2*(22/7)*(42/100)*1
= 2.64 SQM
this is the area covered in one revolution.
area of road = area covered in 750 revolution
= 750*264 SQM
= 1980 sqm
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