Question

9) A rope is placed on the floor in the
shape of an equilateral triangle of side
2.2 m. If this rope is spread out and a
circle is formed out of it, what will be the
radius of the circle?

please tell answer...​

Answer 1

Answer:

1.05 m

Step-by-step explanation:

Equilateral triangle has three sides are same. So, all sides are 2.2 m in length.

The perimeter of the triangle = Sum of three sides

= 2.2+2.2+2.2

=6.6 m

If the rope is spread out, the triangle becomes a single line. So, the length of the line is 6.6 m. No it forms the Circle. When a rope is to be form a circle, the length of a rope becomes the Perimeter of the Circle.

So, the perimeter of the circle= 6.6 m

perimeter of the circle= 2πr

2πr = 6.6

2×(22/7)×r = 6.6

r = (6.6×7)÷(2×22)

radius (r)= 1.05 m

Answer 2

Answer:

Radius of semi-circle = 7√2/ 2 cm. Area of semi-circle = π/2 × (7√2/ 2) 2. By further calculation = ½ × 22/7 × 98/4 = 77/2 cm 2. Area of the shaded region = Area of the semi-circle – Area of ABC. Substituting the values = 77/2 – 49/2 = 28/2 = 14 cm 2. 25. A circular field has perimeter 660 m. A plot in the shape of a square having ...

Step-by-step explanation:

hope it helps