Question

9 a square - 4 b square - 3a - 2b​

Answer 1

Step-by-step explanation:

  9(a^2) - 4(b^2) - 3a - 2b

= [ (3a)^2 - (2b)^2 ] - ( 3a + 2b)

= [ (3a - 2b) (3a + 2b) ] - (3a + 2b)  [By using the identity a^2 - b^2 = (a-b)(a+b)]

= (3a + 2b) (3a - 2b - 1)  (By taking common from both sides)

I hope this is the answer you are looking for..

Answer 2

Answer:

full explanation

Step-by-step explanation:

thnk uh