9. A stone is dropped from a certain height on earth
and it takes 12 seconds to reach the ground. If the
same stone is dropped from the same height on
moon, find the time that it will take to reach the
surface of the moon. (Ignore the air resistance).
GIVE CORRECT ANSWER
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Answers
Answered by
1
Answer:
By second equation of Newton we have
S=ut+
2
1
at
2
Here u=0
a=g
S=h=1cm
For the stome in moon, g
′
=
6
g
∴h=
2×6
g
t
2
∴t=
12
g
h
=
6
sec
Answered by
0
29.39 Sec
Time taken by stone at earth t = 12 sec
at earth a = g
So H = 1/2 g t^2
H = 5 * 12^2
At moon a = 6g
So H = 1/2 g/6 t^2
144 * 5 = 1/2 * 10/6 * t^2
Thus t = 29.39 Sec
Time taken by stone at earth t = 12 sec
at earth a = g
So H = 1/2 g t^2
H = 5 * 12^2
At moon a = 6g
So H = 1/2 g/6 t^2
144 * 5 = 1/2 * 10/6 * t^2
Thus t = 29.39 Sec
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