Question

9.A sum of Rs. 1000 is invested at 8% simple interest per year.

(a) Find the interest at the end of first year.

(b) Find the interest at the end of second year.

(c) Find the interest at the end of third year.

(d) Does these interests form an A.P.? Explain why?

(e) Find the interest at the end of thirty years?​

Answer 1

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$the \: interest \: at \: the \: end \: of \: first \: year = \frac{1000 \times 8 \times 1}{100} \\ = 80$

$the \: interest \: at \: the \: end \: of \: second\: year = \frac{1000 \times 8 \times 2}{100} \\ = 160$

$the \: interest \: at \: the \: end \: of \: third \: year = \frac{1000 \times 8 \times 3}{100} \\ = 240$

Yes, they form an AP series as common difference is same.

$the \: interest \: at \: the \: end \: of \: 30 \: year = \frac{1000 \times 8 \times 30}{100} \\ = 2400$

$\color{green}{•••hope \: it \: helps \: you•••}$