Question

9. A sum of Rs 800 is in the form of denominations of Rs 10 and Rs 20. If the total number
of notes be 50, find the number of notes of each type,
10. Seeta Devi has Rs 9 in fifty-paise and twenty five-paise coins. She has twice as many
twenty-five paise coins as she has fifty-paise coins. How many coins of each kind does
she have?​

Answer 1

Answer:

20rs. note==30

={20×30=600}

__and__

10rs. note==20

={10×20=200}

___,,___now___,,___

600+200=800

Answer 2

Step-by-step explanation:

9. Total amt=800

Total no of notes=50

Denominations=10 and 20

Let no of 10 rupee notes will be 50-x

amt=500-10x ......1

And no of 20 rupee notes be x

amt=20x.......2

So, 20x + 500-10x

800=10x + 500

300=10x

x= 300/10

x=30

Number of 20 rupee notes=30

Number of 10 rupee notes =20