Question

9.
A swimming pool of dimension 50 mx 30 mx 2 m needs to be tiled with tiles of
dimension 20 cm x 20 cm. If one tile costs 1.5, find the total cost of tiling. (Walls and
floor need to be covered with tiles)​

Answer 1

ANSWER

Length of swimming pool l=30m

Breadth of swimming pool b=20m

Height of swimming pool h=1.5m

The total surface area of pool= Lateral surface area + Area of base

                                                 =2h(l+b)+(l×b)

                                                 =2×1.5(30+20)+(30×20)

                                                 =750m2

Side of square tile a=50cm=0.5m

Area of 1 tile =a×a=0.5×0.5=0.25m2

Number of tiles =area of tilearea of pool

                           =0.25750

Number of tiles =3000

Therefore 3000 tiles are required.