Question

9. A tensile bar is stressed to 250 N/mm' which is beyond its elastic limit. At this stage the strain produced in the bar is observed to be 0.0014. If the modulus of elasticity of the material of the bar is 205000 N/mm. then the elastic component of the strain is very close to [IAS-1997) (a) 0.0004 (b) 0.0002 (c) 0.0001 (d) 0.00005​

Answer 1

Answer:

का खेत में साक्षात्कार कुछ का अर्थ रखता है और इसका आशय स्पष्ट कीजिए

Answer 2

Concept Introduction:-

Stress causes a medium or object to deform.

Given Information:-

We have been given that a tensile bar is stressed to $250$ N/mm' which is beyond its elastic limit. At this stage the strain produced in the bar is observed to be $0.0014$

To Find:-

We have to find that the elastic component of the strain.

Solution:-

According to the problem

Strain$=(\frac{250}{205000})-0.0014\\=0.0002$

Final Answer:-

The option (b) is correct option.