9. A train 180 m long passes a platform 300 m
long at a speed of 80 km/h. Find the time
taken by the train.
Answers
Answered by
2
Step-by-step explanation:
Since the electric pole is a single entity having negligible thickness the time taken by a train 180m long running at a speed of 90km/hr or 90000m/60 min = 180 *60/90000 = 0.12 min or 7.2 sec to pass the pole.
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Related Questions (More Answers Below)
Answered by
0
Step-by-step explanation:
Let l and s be the length of train and speed of train respectively.
now,
Length of platform =300m
Time taken by the train to cross the signal =
Speed of train
length of train
⇒
s
l
=12
⇒l=12s.....(1)
Now,
Time taken by the train to cross the platform =
speed of train
length of train+length of platform
⇒30=
s
l+300
⇒30s=12s+300(From (1))
⇒30s−12s=300
⇒s=
18
300
=
3
50
m/s=
3
50
×
5
18
=60km/hr
Hence the speed of the train is 60km/hr
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