Question

9. A train crosses a platform 90 m long in 30 seconds and a man standing on the platform in 15 seconds.
Find the speed of the train.
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Answer 1

Answer:

Case 1:

d=(90+x)m

t=30s

s=(90+x)/30

Case 2:

d=x m

t=15 s

s=x/15

x/15=(90+x)/30

x=(90+x)/2

2x=90+x

x=90 m

Length of train =90 m

Speed =x/15 m/s

=90/15m/s

=6 m/s.

# A student of class 10.

#Hope it helps.

# PLZZZZ mark brainliest

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