Physics, asked by hetalmajhi, 9 days ago

9. A train starting from rest attains a velocity of 72 km h in 5 minutes. Assuming that the acceleration is uniform, find the (a) acceleration, and (b) distance travelled by the train for attaining this velocity.​

Answers

Answered by yasirrajput1124
0

Answer:

acceleration = 1/15 ms-2

distance = 3km

Explanation:

v=u+at

a=(v-u)/t -----------(1)

v=72 km/h

=20m/s

u=0

t=5*60 sec =300sec

by putting values of v,u,t in (1)

a=1/15 m/s2

s=ut +(1/2)at2

=0+(1/2)(1/15)(300)(300)

=3km

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