Question

9. A vertical tower stands on a horizontal plane and is surmounted
of height 5 metres. At a point on the plane, the angles of elevation of
top of the flag-staff are respectively 30° and 60°. Find the height oft
inted by a vertical
cation of the botto
e height of the tower​

Answer 1

Answer:

Just multiply you'll get the ans

Answer 2

Answer:

The height is 2.5 m

Given:

Height of flagstaff = 5 m

Step-by-step explanation:

Let the height of the tower be h meters.

The following is the figure for the given problem.

We know that,

\tan \theta=\frac{\text {Adjacent side}}{\text {Opposite side}}tanθ=

Opposite side

Adjacent side

From triangle ABC,

\tan 30=\frac{h}{B C}tan30=

BC

h

h=B C\left(\frac{1}{\sqrt{3}}\right)h=BC(

3

1

)

B C=\sqrt{3}(h)BC=

3

(h)

From triangle PBC,

\tan 60=\frac{P B}{B C}tan60=

BC

PB

\sqrt{3}=\frac{\mathrm{h}+5}{\mathrm{BC}}

3

=

BC

h+5

B C \sqrt{3}=\mathrm{h}+5BC

3

=h+5

On substituting the value of BC, we get,

\sqrt{3} h(\sqrt{3})+5

3

h(

3

)+5

3 h=h+53h=h+5

2 h=52h=5