Question

9. A wire of given material having length 1 and area of cross-section A has a resistance of 422. What
would be the resistance of another wire of the same material having length 1/2 and area of cross-section
2A?

Answer 1

Answer:

Explanation:

R=specific resistance×length/area

For first case,

422=specific resistance×1/A

From this,

Specific resistance=422A.

For second case,

R=422A/2A×2. (as same material is used, specific resistance will be same)

R=211/2

R=105.5 ohm