9 A5 kg sphere is projected vertically upward with a speed of 20 ms' It rises to a height of 12 m. The energy used up in overcoming the air resistance is
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Conservation of energy is the best way to solve these type of problems.
The ball initially only has kinetic energy =
KE=12mv2=12(5)(20)2=1000JKE=12mv2=12(5)(20)2=1000J
The kinetic energy is converted to potential energy and energy used in overcoming air resistance:
KE=PE+EfricKE=PE+Efric
or
12mv2=mgh+Efric12mv2=mgh+Efric
or
1000Nm=(5)(9.81)(12)+Efric1000Nm=(5)(9.81)(12)+Efric
EfricEfric=411J
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