Question

9. An element 'X' belongs to third period and
second group of the Modern Periodic Table. [3]
a) Write its electronic configuration
b) Is it a metal or non-metal? Why?
c) Write the formula of the compound formed
when 'X' reacts with an element
(i)Y of electronic configuration 2,6 and
(ii) Z with electronic configuration 2, 8, 7.​

Answer 1

a) Electric configuration =-2,8,2

b) It is a Metal.

c)

(i) x^+2 y^-2

2 2

Compound 7=-xy

(ii) x^+2 z^-1

2 1

Compound= -xz2

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Answer 2

Answer:

a) since it belongs to third period ,  it has three shells

   and it belongs to second period. So ,  it has 2 valence electrons

   So , Electronic configuration = 2,8,2

b)it is a metal

  because elements which have 1,2,3 electrons in their outermost shell are metals

c)

i) Y = 2,6

 since it has six valency electrons ,  it's valency is -2

 so when we use criss cross method,

 X³⁺         Y²⁻

 it forms X₂Y₃

ii)Z= 2,8,7

  since it has seven valence electrons , it's valency is -1

  the same way as above,

   X³⁺        Z¹⁻

   it forms XZ₃

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